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Question Number 186126 by Mingma last updated on 01/Feb/23

Commented by Frix last updated on 01/Feb/23

$$\tan 2\alpha =\frac{2\tan \alpha }{1-{\tan }^2\alpha }\Rightarrow$$$$\tan 4\alpha =\tan \left(2\times \left(2\alpha \right)\right)=\frac{4(1-{\tan }^2\alpha )\tan \alpha }{1-{6\tan }^2\alpha +{\tan }^4\alpha }$$

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