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Question Number 186130 by yaslm last updated on 01/Feb/23

Commented by Frix last updated on 01/Feb/23

$$x^{\frac{p}{\ln x}}={\mathrm{e}}^p{x}^{\frac{\ln p}{\ln x}}=p{x}^{\frac{q\ln p}{\ln x}}=p^q$$

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