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Question Number 186163 by Rupesh123 last updated on 01/Feb/23

	Answered by Frix last updated on 01/Feb/23

	$x = \pm 4$
	Answered by aba last updated on 01/Feb/23

	$x = \pm 4$
	Answered by manolito last updated on 02/Feb/23

	$5 + x = a^{2} 5 - x = b^{2}$ $a^{2} + b^{2} = 10 a^{2} - b^{2} = 2 x x = \frac{a^{2} - b^{2}}{2}$ $\frac{3 + \frac{a^{2} - b^{2}}{2}}{a} + \frac{3 - \frac{a^{2} - b^{2}}{2}}{b} = \frac{4}{3}$ $u s a r a^{2} + b^{2} = 10 e n e l d e s a r r o l l o$ $3 (a + b) [a b - 2] = 4 a b$ $a = 3 5 + x = 9 x = 4 b = \pm 1$ $b = 3 5 - x = 9 x = - 4 a = \pm 1$ $a = a + b b = 0 f a l s e$ $c o n t i n u a r a . . . . . . . . .$ $\frac{}{}$
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