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Question Number 186236 by ajfour last updated on 02/Feb/23

Answered by a.lgnaoui last updated on 02/Feb/23

$$1$$

Commented by ajfour last updated on 02/Feb/23

$$Itsquitesimple{x}_{min}=\frac{1}{\sqrt{3}}$$

Commented by mr W last updated on 02/Feb/23

$$when\alpha \to 0,x\to 0.$$$$thatmeansthereisnominimumfor$$$$x.$$

Commented by mr W last updated on 02/Feb/23

Commented by mr W last updated on 03/Feb/23

$$\frac{x}{1}=\frac{\sin \alpha }{\sin (\frac{\pi }{3}+\alpha +\alpha )}$$$$x=\frac{\sin \alpha }{\sin (\frac{\pi }{3}+2\alpha )}\underset{\alpha \to 0}{\to }0$$$$x=\frac{\sin \alpha }{\sin (\frac{\pi }{3}+2\alpha )}\underset{\alpha \to \frac{\pi }{3}}{\to }\mathrm{\infty }$$$$\Rightarrow xhasnominimumandmaximum.$$

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