All Questions Topic List
Integration Questions
Previous in All Question Next in All Question
Previous in Integration Next in Integration
Question Number 186352 by normans last updated on 03/Feb/23
∫12tan−1(x)+2x2dx
Answered by MJS_new last updated on 04/Feb/23
∫2+arctanxx2dx=2∫dxx2+∫arctanxx2dx2∫dxx2=−2x+C1∫arctanxx2dx=−arctanxx+∫dxx(x2+1)∫dxx(x2+1)=∫(1x−xx2+1)dx=12lnx2x2+1+C2⇒answeris1−ln5−3ln22+12arctan12
Terms of Service
Privacy Policy
Contact: info@tinkutara.com