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Question Number 186402 by Rupesh123 last updated on 04/Feb/23

Answered by mr W last updated on 04/Feb/23

Commented by mr W last updated on 04/Feb/23

sin α=((4 sin 75°)/6) ⇒((sin 75°)/(sin α))=(6/4)=(3/2) θ=105°−α γ=θ−30°=75°−α (x/(sin α))=((4+6)/(sin θ)) ⇒x=((10 sin α)/(sin θ)) (y/(sin 30°))=(x/(sin γ)) ⇒y=(x/(2 sin γ)) green area=((xy sin θ)/2) =((25 sin^2 α)/(cos (α+15°) cos (α−15°))) =((25 sin^2 α)/(cos^2 15−sin^2 α)) =((25)/((((sin 75°)/(sin α)))^2 −1)) =((25)/(((3/2))^2 −1))=20 ✓

$$\mathrm{sin}\:\alpha=\frac{\mathrm{4}\:\mathrm{sin}\:\mathrm{75}°}{\mathrm{6}} \\ $$$$\Rightarrow\frac{\mathrm{sin}\:\mathrm{75}°}{\mathrm{sin}\:\alpha}=\frac{\mathrm{6}}{\mathrm{4}}=\frac{\mathrm{3}}{\mathrm{2}} \\ $$$$\theta=\mathrm{105}°−\alpha \\ $$$$\gamma=\theta−\mathrm{30}°=\mathrm{75}°−\alpha \\ $$$$\frac{{x}}{\mathrm{sin}\:\alpha}=\frac{\mathrm{4}+\mathrm{6}}{\mathrm{sin}\:\theta} \\ $$$$\Rightarrow{x}=\frac{\mathrm{10}\:\mathrm{sin}\:\alpha}{\mathrm{sin}\:\theta} \\ $$$$\frac{{y}}{\mathrm{sin}\:\mathrm{30}°}=\frac{{x}}{\mathrm{sin}\:\gamma} \\ $$$$\Rightarrow{y}=\frac{{x}}{\mathrm{2}\:\mathrm{sin}\:\gamma} \\ $$$${green}\:{area}=\frac{{xy}\:\mathrm{sin}\:\theta}{\mathrm{2}} \\ $$$$=\frac{\mathrm{25}\:\mathrm{sin}^{\mathrm{2}} \:\alpha}{\mathrm{cos}\:\left(\alpha+\mathrm{15}°\right)\:\mathrm{cos}\:\left(\alpha−\mathrm{15}°\right)} \\ $$$$=\frac{\mathrm{25}\:\mathrm{sin}^{\mathrm{2}} \:\alpha}{\mathrm{cos}^{\mathrm{2}} \:\mathrm{15}−\mathrm{sin}^{\mathrm{2}} \:\alpha} \\ $$$$=\frac{\mathrm{25}}{\left(\frac{\mathrm{sin}\:\mathrm{75}°}{\mathrm{sin}\:\alpha}\right)^{\mathrm{2}} −\mathrm{1}} \\ $$$$=\frac{\mathrm{25}}{\left(\frac{\mathrm{3}}{\mathrm{2}}\right)^{\mathrm{2}} −\mathrm{1}}=\mathrm{20}\:\checkmark \\ $$

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