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Question Number 186489 by Mingma last updated on 05/Feb/23

Answered by Frix last updated on 06/Feb/23

$$a^2+b^2+c^2={1981}^2=7^2\times {283}^2$$$$2^2+3^2+6^2=7^2$$$${\left(2\times 283\right)}^2+{\left(3\times 283\right)}^2+{\left(6\times 283\right)}^2={\left(7\times 283\right)}^2$$$${566}^2+{849}^2+{1698}^2={1981}^2$$

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