Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 186500 by 073 last updated on 05/Feb/23

$$\underset{x\to +\mathrm{\infty }}{\lim }\sqrt{\mathrm{x}+\sqrt{\mathrm{x}+\sqrt{\mathrm{x}+\sqrt{\mathrm{x}}}}}-\sqrt{\mathrm{x}}=?$$$$\mathrm{please}\mathrm{solution}$$

Answered by greougoury555 last updated on 05/Feb/23

$$\underset{x\to \mathrm{\infty }}{\lim }\frac{\sqrt{x+\sqrt{x+\sqrt{x}}}}{\sqrt{x+\sqrt{x+\sqrt{x+\sqrt{x}}}}+\sqrt{x}}$$$$=\underset{x\to \mathrm{\infty }}{\lim }\frac{\sqrt{x}\left(\sqrt{1+\sqrt{\frac{1}{x}+\sqrt{\frac{1}{x}}}}\right)}{\sqrt{x}(\sqrt{1+\sqrt{\frac{1}{x}+\sqrt{\frac{1}{x^2}+\sqrt{\frac{1}{x^4}}}}}+1)}$$$$=\frac{1}{2}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com