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Question Number 186557 by Mingma last updated on 06/Feb/23

	Answered by mr W last updated on 06/Feb/23

	$h = h e i g h t o f t r a p e z o i d$ $a r e a o f t r a p e z o i d = \frac{(5 + 6) h}{2}$ $a r e a o f t r i a n g l e w i t h b a s e b = \frac{b h}{2}$ $w h i c h i s a t h i r d o f t h e t o t a l a r e a,$ $t h e r e f o r e$ $\frac{b h}{2} = \frac{1}{3} \times \frac{(5 + 6) h}{2}$ $\Rightarrow b = \frac{5 + 6}{3} = \frac{11}{3}$ $a = 5 - b = 5 - \frac{11}{3} = \frac{4}{3}$ $\Rightarrow \frac{a}{b} = \frac{4}{11} ✓$
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