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Question Number 186691 by 073 last updated on 08/Feb/23

Answered by Ar Brandon last updated on 08/Feb/23

$${\tan }^{-1}\left(\cot x\right)=\frac{\pi }{2}-{\tan }^{-1}\left(\tan x\right)=\frac{\pi }{2}-x$$$$\int {\tan }^{-1}\left(\cot x\right)dx=\int (\frac{\pi }{2}-x)dx$$

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