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Question Number 186901 by Beginner last updated on 11/Feb/23

Answered by Frix last updated on 12/Feb/23

$$\mathrm{The}\mathrm{chance}\mathrm{for}\mathrm{the}\mathrm{jackpot}\mathrm{is}$$$$P=\frac{1}{C_7^{40}}=\frac{1}{18643560}$$$$\mathrm{The}\mathrm{chance}\mathrm{to}not\mathrm{win}\mathrm{in}n\mathrm{games}\mathrm{is}$$$${(1-P)}^n={\left(\frac{18643559}{18643560}\right)}^n$$$$\mathrm{The}\mathrm{chance}\mathrm{to}\mathrm{win}\mathrm{at}\mathrm{least}\mathrm{once}\mathrm{is}$$$$1-{(1-P)}^n$$$$n=15\times 30\times 52=23400$$$$\Rightarrow \mathrm{answer}\mathrm{is}\approx .00125\mathrm{or}.125\mathrm{\%}$$$$$$$$[\mathrm{For}\mathrm{a}50\mathrm{\%}\mathrm{chance}\mathrm{you}\mathrm{must}\mathrm{play}\mathrm{at}\mathrm{least}$$$$12922732\mathrm{times}]$$

Commented by Beginner last updated on 12/Feb/23

$$Thanks$$

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