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Question Number 186966 by 073 last updated on 12/Feb/23

Commented by 073 last updated on 12/Feb/23

$$\mathrm{solution}?$$

Commented by 073 last updated on 12/Feb/23

$$\mathrm{i}\mathrm{need}\mathrm{it}\mathrm{please}$$$$\mathrm{solution}??$$

Answered by Rasheed.Sindhi last updated on 13/Feb/23

$$a\ast b=2a+2b-ab-(b\ast a)$$$$a\mathrm{\&}bareexchangeable\Rightarrow a\ast b=b\ast a$$$$2(a\ast b)=2a+2b-ab$$$$a\ast b=a+b-\frac{ab}{2}$$$$(-2)\ast 3=-2+3-\frac{(-2)\left(3\right)}{2}=-2+6=4$$

Commented by 073 last updated on 14/Feb/23

$$\mathrm{nice}\mathrm{solution}$$$$\mathrm{thank}\mathrm{you}$$

Commented by mr W last updated on 16/Feb/23

$$from$$$$a\ast b=2a+2b-ab-(b\ast a)$$$$wecannotdeviatethat$$$$a\mathrm{\&}bareexchangeable\Rightarrow a\ast b=b\ast a.$$$$wecanonlysay$$$$a\ast b+b\ast a=2a+2b-ab.$$$$$$$$soithinkthequestionisnotsolvable$$$$withgivenconditions.$$

Commented by Rasheed.Sindhi last updated on 16/Feb/23

$$\mathbb{T}\mathbf{han}\mathbb{k}\mathbf{s}\mathbf{a}\mathbf{lot}\mathbf{sir}!$$

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