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Question Number 187008 by mustafazaheen last updated on 12/Feb/23

(a/3)=(b/4)=(c/5)           3a+c=42        b=?  how is solution

a3=b4=c53a+c=42b=?howissolution

Answered by HeferH last updated on 12/Feb/23

(a/3) = (c/5)   (a/c) = (3/5) ; a = 3k , c = 5k    3(3k) + 5k = 42   14k = 42   k = ((42)/(14)) = 3    c = 5(3) = 15    b = (4/5)∙ c   b = ((4∙15)/5) = 12

a3=c5ac=35;a=3k,c=5k3(3k)+5k=4214k=42k=4214=3c=5(3)=15b=45cb=4155=12

Answered by Rasheed.Sindhi last updated on 12/Feb/23

(a/3)=(b/4)=(c/5)           3a+c=42        b=?  ((3a)/9)=(c/5)=((3a+c)/(9+5))=((42)/(14))=3  (b/4)=3⇒b=12

a3=b4=c53a+c=42b=?3a9=c5=3a+c9+5=4214=3b4=3b=12

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