Question Number 18704 by gourav~ last updated on 28/Jul/17
Answered by Principal last updated on 28/Jul/17
$$\mathrm{Circumference}\:\mathrm{of}\:\mathrm{circular}\:\mathrm{wire} \\ $$$$=\:\mathrm{2}\pi×\mathrm{7}.\mathrm{5}\:=\:\mathrm{15}\pi\:\mathrm{cm} \\ $$$$\theta\:=\:\frac{{l}}{{r}}\:=\:\frac{\mathrm{15}\pi\:\mathrm{cm}}{\mathrm{120}\:\mathrm{cm}}\:=\:\frac{\pi}{\mathrm{8}}\:\mathrm{rad}\:=\:\mathrm{22}.\mathrm{5}° \\ $$