(a/x)=(b/y)=(c/z)=(1/3) ,a−2b+c=2 and 2y−3z=1 x=? how is solution this qution solve by the Properties of proportion


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Question Number 187087 by mustafazaheen last updated on 13/Feb/23

$\frac{a}{x} = \frac{b}{y} = \frac{c}{z} = \frac{1}{3}, a - 2 b + c = 2 a n d 2 y - 3 z = 1 x = ?$ $h o w i s s o l u t i o n$ $t h i s q u t i o n s o l v e b y t h e Properties of proportion$
Commented by mr W last updated on 13/Feb/23

$a s i s a i d i n Q 187020, y o u {c a n}^{'} t$ $d e t e r m i n e 6 u n k n o w n s w h e n y o u$ $o n l y h a v e 5 c o n d i t i o n s .$ $i f y o u {d o n}^{'} t a c c e p t m y a n s w e r, y o u$ $c a n c o m m e n t t h e r e i n s t e a d o f$ $p o s t i n g t h e s a m e q u e s t i o n h e r e$ $a g a i n .$
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