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Question Number 187190 by 073 last updated on 14/Feb/23

Answered by aba last updated on 14/Feb/23

xΔe=x⇒−3x×e−3x−3e−4=x ⇒−3e(x+1)=4(x+1)⇒ e=−(4/3)

xΔe=x⇒−3x×e−3x−3e−4=x⇒−3e(x+1)=4(x+1)⇒e=−43

Commented by 073 last updated on 15/Feb/23

thanks

thanks

Answered by HeferH last updated on 14/Feb/23

x △ y = −3xy −3x −3y − 4 x △ e = x x = −3xe−3x−3e−4 4x + 4 = −3xe − 3e e(3x + 3) = −4 −4x e = ((−4−4x)/(3x+3)) = ((−4(1 + x))/(3(1 + x))) = −(4/3)

x△y=−3xy−3x−3y−4x△e=xx=−3xe−3x−3e−44x+4=−3xe−3ee(3x+3)=−4−4xe=−4−4x3x+3=−4(1+x)3(1+x)=−43

Commented by 073 last updated on 15/Feb/23

thanks alot

thanksalot

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