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Question Number 18748 by khamizan833@yahoo.com last updated on 29/Jul/17

Answered by Joel577 last updated on 29/Jul/17

$$f\left(x\right)={(x-1)}^3-6x$$$$f(1+\sqrt[3]{2}+\sqrt[3]{4})={(\sqrt[3]{2}+\sqrt[3]{4})}^3-6(1+\sqrt[3]{2}+\sqrt[3]{4})$$$$=(2+3\sqrt[3]{16}+3\sqrt[3]{32}+4)-(6+6\sqrt[3]{2}+6\sqrt[3]{4})$$$$=6+6\sqrt[3]{2}+6\sqrt[3]{4}-6-6\sqrt[3]{2}-6\sqrt[3]{4}$$$$=0$$

Commented by khamizan833@yahoo.com last updated on 30/Jul/17

$$\mathrm{Thank}\mathrm{you}\mathrm{sir}$$

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