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Question Number 187549 by Rupesh123 last updated on 18/Feb/23

Answered by HeferH last updated on 18/Feb/23

$$Theheightof△BICistheinradius.$$$$Area=s\cdot I$$$$\frac{\sqrt{s(s-a)(s-b)(s-c)}}{s}=I$$$$s=\frac{7+9+12}{2}=14$$$$I=\sqrt{\frac{(14-9)(14-7)(14-12)}{14}}=\sqrt{5}$$$$AreaofBIC=\frac{12\cdot \sqrt{5}}{2}=6\sqrt{5}{u}^2$$

Commented by Rupesh123 last updated on 18/Feb/23

Great, bro!

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