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Question Number 187874 by mustafazaheen last updated on 23/Feb/23

how is solution  ((√2)−1)^(13) =x          ((√2)+1)^(221) =?  1)x^(−16)           2)x^(−17)              3)x^(221)             4)x^(21)

howissolution(21)13=x(2+1)221=?1)x162)x173)x2214)x21

Answered by som(math1967) last updated on 23/Feb/23

 ((√2)+1)((√2)−1)=1  ⇒((√2)−1)=(1/( (√2)+1))   ((√2)−1)^(13) =x  ⇒(1/(((√2)+1)^(13) ))=x  ⇒((√2)+1)^(13) =(1/x)  ⇒{((√2)+1)^(13) }^(17) =(1/x^(17) )  ((√2)+1)^(221) =x^(−17)

(2+1)(21)=1(21)=12+1(21)13=x1(2+1)13=x(2+1)13=1x{(2+1)13}17=1x17(2+1)221=x17

Answered by Sutrisno last updated on 23/Feb/23

((√2)+1)^(221) .((((√2)−1)^(221) )/(((√2)−1)^(221) ))  =(1/((((√2)−1)^(13) )^(17) ))  =(1/x^(17) )  =x^(−17)

(2+1)221.(21)221(21)221=1((21)13)17=1x17=x17

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