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Question Number 187701 by Mingma last updated on 20/Feb/23

	Answered by HeferH last updated on 20/Feb/23

	$l e t ‘ ‘ h^{″} b e t h e h e i g h t o f t h e t o p t r i a n g l e a n d ‘ ‘ a^{″}$ $t h e b a s e$ $\frac{7 a h}{2} = 28$ $a h = \frac{28 \cdot 2}{7} = 8$ $T o t a l a r e a = 4 a \cdot 4 h \cdot \frac{1}{2} = 8 a h = 64 u^{2}$
	Commented by Mingma last updated on 20/Feb/23
	Good
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