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Question Number 187730 by otchereabdullai last updated on 20/Feb/23
Evaluatelim(x,y)→(0,0)x2(y−1)2x2+(y−1)2
Answered by mr W last updated on 21/Feb/23
lim(x,y)→(0,0)x2(y−1)2x2+(y−1)2=02(0−1)202+(0−1)2=01=0
Commented by otchereabdullai last updated on 21/Feb/23
thankyoumysupperprofW
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