All Questions Topic List
Geometry Questions
Previous in All Question Next in All Question
Previous in Geometry Next in Geometry
Question Number 187765 by Tawa11 last updated on 21/Feb/23
Answered by cortano12 last updated on 21/Feb/23
(1i)⇒(x−1)(x−3)+(y−3)(y−7)=0⇒x2+y2−4x−10y+24=0
(1.2)r=∣4∣=4⇒(x−3)2+(y−4)2=16⇒x2+y2−6x−8y+9=0
Answered by floor(10²Eta[1]) last updated on 21/Feb/23
(1):AB=2ı+4ȷ⇒∥AB∥=4+16=20=25⇒radius=5Center:(3+12,7+32)=(2,5)⇒(x−2)2+(y−5)2=5(2):r=4(x−3)2+(y−4)2=16
Terms of Service
Privacy Policy
Contact: info@tinkutara.com