please help me to solve 6x^2 +x−2=0


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Question Number 187951 by chhuangakawlni last updated on 24/Feb/23

$p l e a s e h e l p m e t o s o l v e$ $6 x^{2} + x - 2 = 0$
	Answered by cortano12 last updated on 24/Feb/23

	$(x + \frac{4}{6}) (x - \frac{3}{6}) = 0$ ${\begin{cases} x = - \frac{2}{3} \\ x = \frac{1}{2} \end{cases}$
	Answered by Rasheed.Sindhi last updated on 24/Feb/23

	$6 x^{2} + 4 x - 3 x - 2 = 0$ $2 x (3 x + 2) - (3 x + 2) = 0$ $(3 x + 2) (2 x - 1) = 0$ $3 x + 2 = 0 ∣ 2 x - 1 = 0$ $x = - \frac{2}{3} ∣ x = \frac{1}{2}$
	Answered by HeferH last updated on 25/Feb/23
	$6x^2 + x − 2 = 0 6x^2 + 4x − 3x −2=0 2x(3x + 2) −1(3x + 2) = 0 (2x − 1)(3x + 2)=0 { ((2x−1 = 0; x = (1/2))),((3x + 2 = 0; x = −(2/3) )) :}$
	$6 x^{2} + x - 2 = 0$ $6 x^{2} + 4 x - 3 x - 2 = 0$ $2 x (3 x + 2) - 1 (3 x + 2) = 0$ $(2 x - 1) (3 x + 2) = 0$ ${\begin{cases} 2 x - 1 = 0; x = \frac{1}{2} \\ 3 x + 2 = 0; x = - \frac{2}{3} \end{cases}$
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