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Question Number 187953 by Mingma last updated on 24/Feb/23

Answered by som(math1967) last updated on 24/Feb/23

$$△AOB=△AOC=△AOC=\frac{1}{3}△ABC$$$$=\frac{1}{3}\times 48=16{cm}^2$$$$△AOM=\frac{1}{2}△AOB=8{cm}^2$$$$[OMismedianof△AOB]$$$$△AOK=\frac{1}{2}△AOC=8{cm}^2$$$$S_{AMOK}=△AOM+△AOK=8+8=16{cm}^2$$

Commented by som(math1967) last updated on 24/Feb/23

Commented by Mingma last updated on 24/Feb/23

Very nice, sir!

Answered by HeferH last updated on 24/Feb/23

$$2\left(\frac{S_{ABC}}{6}\right)=S_{AMOK}$$$$S_{AMOK}=16{cm}^2$$

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