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Question Number 1880 by alib last updated on 20/Oct/15

Solve    1) (sin 2x+ (√)3 cos 2x)^2 =2 −2 cos (((2π)/3)−x)  2) cos x − cos 2x = sin 3x    3) sin (15 °+x) + cos (45°+x)+ (1/2)=0  4) tan (70°+x) + tan (20°−x) = 2

$${Solve} \\ $$$$ \\ $$$$\left.\mathrm{1}\right)\:\left({sin}\:\mathrm{2}{x}+\:\sqrt{}\mathrm{3}\:{cos}\:\mathrm{2}{x}\right)^{\mathrm{2}} =\mathrm{2}\:−\mathrm{2}\:{cos}\:\left(\frac{\mathrm{2}\pi}{\mathrm{3}}−{x}\right) \\ $$$$\left.\mathrm{2}\right)\:{cos}\:{x}\:−\:{cos}\:\mathrm{2}{x}\:=\:{sin}\:\mathrm{3}{x} \\ $$$$ \\ $$$$\left.\mathrm{3}\right)\:{sin}\:\left(\mathrm{15} °+{x}\right)\:+\:{cos}\:\left(\mathrm{45}°+{x}\right)+\:\frac{\mathrm{1}}{\mathrm{2}}=\mathrm{0} \\ $$$$\left.\mathrm{4}\right)\:{tan}\:\left(\mathrm{70}°+{x}\right)\:+\:{tan}\:\left(\mathrm{20}°−{x}\right)\:=\:\mathrm{2} \\ $$$$ \\ $$

Answered by alib last updated on 20/Oct/15

ASAP

$${ASAP} \\ $$

Commented by Rasheed Soomro last updated on 21/Oct/15

What do you mean by ′ASAP ′ ?

$${What}\:{do}\:{you}\:{mean}\:{by}\:'{ASAP}\:'\:? \\ $$

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