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Question Number 188035 by Michaelfaraday last updated on 25/Feb/23
solve∫x2(a+bx)2dx
Answered by MJS_new last updated on 25/Feb/23
∫x2(a+bx)2dx==1b2∫dx−2ab2∫dxa+bx+a2b2∫dx(a+bx)2==xb2−a2b3(a+bx)−2ab3ln∣a+bx∣+C
Commented by Michaelfaraday last updated on 01/Mar/23
thankssir
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