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Question Number 188036 by Michaelfaraday last updated on 25/Feb/23
∫2xexdx
Answered by MJS_new last updated on 25/Feb/23
∫2xexdx=∫e(1+ln2)xdx=e(1+ln2)x1+ln2==2xex1+ln2+C
Commented by Michaelfaraday last updated on 01/Mar/23
thankssir
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