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Question Number 188059 by normans last updated on 25/Feb/23

Answered by nikif99 last updated on 25/Feb/23

$$A+B+C=6\left(1\right)$$$$2A+B=8\left(2\right)$$$$2C+E=6\left(3\right)$$$$A+D+E=9\left(4\right)$$$$B+2D=6\left(5\right)$$$$B+\frac{D}{C}=6\left(6\right)$$$$\left(5\right)\left(6\right)\Rightarrow 2D=\frac{D}{C}\Rightarrow$$$$a:C=\frac{1}{2}orb:D=0$$$$a:\left(3\right)\Rightarrow E=5,\left(1\right)\left(2\right)\Rightarrow A=\frac{5}{2},B=3$$$$\left(4\right)\Rightarrow D=\frac{3}{2}\Rightarrow C+E-A=3$$$$b:\left(5\right)\Rightarrow B=6,\left(2\right)\Rightarrow A=1$$$$\left(1\right)\Rightarrow C=-1,\left(3\right)\Rightarrow E=8$$$$C+E-A=6$$

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