let S be the sets be the sequences of lenght 2018 whose terms are in the sets {1,2,3,4,5,6,10} and sum to 3860. prove that the cardinality of S is at most 2^(3860) ∙( ((2018)/(2048)))^(2018)


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Question Number 188295 by normans last updated on 27/Feb/23
$let S be the sets be the sequences of lenght 2018 whose terms are in the sets {1,2,3,4,5,6,10} and sum to 3860. prove that the cardinality of S is at most 2^(3860) ∙( ((2018)/(2048)))^(2018)$
$l e t S b e t h e s e t s b e t h e s e q u e n c e s o f l e n g h t 2018$ $w h o s e t e r m s a r e i n t h e s e t s {1, 2, 3, 4, 5, 6, 10} a n d s u m t o 3860 .$ $p r o v e t h a t t h e c a r d i n a l i t y o f S i s a t m o s t$ $2^{3860} \cdot {(\frac{2018}{2048})}^{2018}$
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