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Question Number 188320 by normans last updated on 27/Feb/23

           if the on △ABC,     inner circle radius and outer circle radius r and R             show that;        r = 4R sin (A/2) ∙ sin (B/2) ∙ sin (C/2)

iftheonABC,innercircleradiusandoutercircleradiusrandRshowthat;r=4RsinA2sinB2sinC2

Answered by mr W last updated on 28/Feb/23

(a/(sin A))=(b/(sin B))=(c/(sin C))=2R  Δ=((abc)/(4R))=2R^2  sin A  sin B sin C  r=((2Δ)/(a+b+c))    =((2Δ)/(2R(sin A+sin B+sin C)))    =((2R^2  sin A  sin B sin C)/(R(sin A+sin B+sin C)))    =((2R sin A  sin B sin C)/(sin A+sin B+sin C))    =((2R sin A  sin B sin C)/(4 cos (A/2) cos (B/2) cos (C/2)))    =((16R sin (A/2) cos (A/2)  sin (B/2) cos (B/2) sin (C/2) cos (C/2))/(4 cos (A/2) cos (B/2) cos (C/2)))    =4R sin (A/2) sin (B/2) sin (C/2)

asinA=bsinB=csinC=2RΔ=abc4R=2R2sinAsinBsinCr=2Δa+b+c=2Δ2R(sinA+sinB+sinC)=2R2sinAsinBsinCR(sinA+sinB+sinC)=2RsinAsinBsinCsinA+sinB+sinC=2RsinAsinBsinC4cosA2cosB2cosC2=16RsinA2cosA2sinB2cosB2sinC2cosC24cosA2cosB2cosC2=4RsinA2sinB2sinC2

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