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Question Number 188339 by normans last updated on 28/Feb/23

Answered by universe last updated on 28/Feb/23

$$ar(△ABC)=ar\left(ABD\right)+ar\left(ADC\right)$$$$AB.AC\sin (\alpha +\beta )=AB.AD\sin \left(\alpha \right)+AD.AC\sin \left(\beta \right)$$$$\frac{\sin (\alpha +\beta )}{AD}=\frac{\sin \alpha }{AC}+\frac{\sin \beta }{AB}$$$$$$

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