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Question Number 188416 by 073 last updated on 01/Mar/23

Answered by manxsol last updated on 01/Mar/23

$$\mathrm{\Sigma }=\frac{1}{3^2}+\frac{1}{3^3}+.......$$$$\mathrm{\Sigma }=\frac{1}{3}[\frac{1}{3}+\frac{1}{3^2}.......]$$$$3\mathrm{\Sigma }=\frac{1}{3}+\mathrm{\Sigma }$$$$2\mathrm{\Sigma }=\frac{1}{3}$$$$\mathrm{\Sigma }=\frac{1}{6}$$

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