Question and Answers Forum

All Questions      Topic List

Geometry Questions

Previous in All Question      Next in All Question      

Previous in Geometry      Next in Geometry      

Question Number 188444 by Rupesh123 last updated on 01/Mar/23

Answered by mr W last updated on 01/Mar/23

Commented by mr W last updated on 01/Mar/23

a=2×1×sin ((48)/2)=2 sin 24  (a/1)=((sin (x+66+42))/(sin (x+66)))  cos 42+((sin 42)/(tan (x+66)))=2 sin 24  tan (x+66)=((sin 42)/(2 sin 24−cos 42))  ⇒x=tan^(−1) (((sin 42)/(2 sin 24−cos 42)))−66=18°

a=2×1×sin482=2sin24a1=sin(x+66+42)sin(x+66)cos42+sin42tan(x+66)=2sin24tan(x+66)=sin422sin24cos42x=tan1(sin422sin24cos42)66=18°

Commented by Rupesh123 last updated on 01/Mar/23

Perfect ��

Terms of Service

Privacy Policy

Contact: info@tinkutara.com