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Question Number 188898 by Shrinava last updated on 08/Mar/23

$$\mathrm{In}△\mathrm{ABC}\mathrm{holds}:\mathrm{\Sigma }\frac{2+\sqrt{3}\tan \frac{\mathrm{B}}{2}}{1+3{\tan }^2\frac{\mathrm{A}}{2}}⩾\frac{9}{2}$$

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