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Question Number 188901 by Mingma last updated on 08/Mar/23

Answered by Frix last updated on 08/Mar/23

$$AB=\sqrt{8^2+{(10-4)}^2}=10$$$$BC=\sqrt{8^2+{10}^2}=2\sqrt{41}$$$$R_{ABC}=\frac{5\sqrt{41}}{4}$$$$\Rightarrow \mathrm{Answer}\mathrm{is}\frac{1025\pi }{16}-56$$

Commented by Mingma last updated on 08/Mar/23

Excellent!

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