Question and Answers Forum

All Questions      Topic List

Geometry Questions

Previous in All Question      Next in All Question      

Previous in Geometry      Next in Geometry      

Question Number 189054 by mathlove last updated on 11/Mar/23

Answered by som(math1967) last updated on 11/Mar/23

∠EBD=∠HBC ,∠ABC=∠EBF ∠HBF=∠ABD ∠EBD+∠EBF+∠HBF+∠HBC +∠ABC+∠ABD=360 2(∠EBD+∠HBF+∠ABC)=360 ∠EBD+∠HBF+∠ABC=180 ∠EBD+40+n+∠HBF+k+55 +∠ABC+m+90=3×180 m+n+k+185=540−180 m+n+k=360−185=175

∠EBD=∠HBC,∠ABC=∠EBF∠HBF=∠ABD∠EBD+∠EBF+∠HBF+∠HBC+∠ABC+∠ABD=3602(∠EBD+∠HBF+∠ABC)=360∠EBD+∠HBF+∠ABC=180∠EBD+40+n+∠HBF+k+55+∠ABC+m+90=3×180m+n+k+185=540−180m+n+k=360−185=175

Terms of Service

Privacy Policy

Contact: info@tinkutara.com