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Question Number 189079 by pascal889 last updated on 11/Mar/23

Answered by HeferH last updated on 11/Mar/23

$$\sqrt[3]{\frac{1}{7^3}}+\sqrt[3]{\frac{1}{4^3}}-\frac{1}{\sqrt{\frac{4}{9}}}=\frac{1}{7}+\frac{1}{4}-\frac{1}{\left(\frac{2}{3}\right)}=\frac{11}{28}-\frac{3}{2}$$$$=-\frac{31}{28}$$

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