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Question Number 189126 by Mingma last updated on 12/Mar/23
Answered by mr W last updated on 12/Mar/23
if6k⩽n<6k+2:3k+2k+k=n⇒n=6k✓if6k+2⩽n<6k+3:3k+1+2k+k=n⇒n=6k+1→badif6k+3⩽n<6k+4:3k+1+2k+1+k=n⇒n=6k+2→badif6k+4⩽n<6k+6:3k+2+2k+1+k=n⇒n=6k+3→badthatmeansthegeneralsolutionisn=6kwithk∈Zfor0<n<2023thereare337integers:n=6,12,18,...,2016,2022
Commented by Mingma last updated on 13/Mar/23
Excellent!
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