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Question Number 189135 by Shrinava last updated on 12/Mar/23

	Answered by a.lgnaoui last updated on 12/Mar/23

	$(257 - 160) = (264 - 167) = (271 - 174) = . . . . . . = (2112 - 2015)$ $= 97 \Rightarrow s u i t e a r i t m e t i q u e$ $d e r a i s o n : 97; u_{0} = 257$ $u_{n + 1} = 257 (1 + 97 n) (n >= 0)$
	Commented by Shrinava last updated on 13/Mar/23

	$thankyou dearProfessor cool$
	Answered by mr W last updated on 13/Mar/23
	$a={257, 264, 271, ..., 2105, 2112} Σ_(i=1) ^(266) a_i =((266×(257+2112))/2)=266×1184.5 b={160, 167, 174, ..., 2008, 2015} Σ_(i=1) ^(266) b_i =((266×(160+2015))/2)=266×1087.5 average =(Σ/n)=((Σa+Σb)/(2×266)) =((1184.5+1087.5)/2)=1086 ✓$
	$a = {257, 264, 271, . . ., 2105, 2112}$ $\underset{i = 1}{\sum^{266}} a_{i} = \frac{266 \times (257 + 2112)}{2} = 266 \times 1184.5$ $b = {160, 167, 174, . . ., 2008, 2015}$ $\underset{i = 1}{\sum^{266}} b_{i} = \frac{266 \times (160 + 2015)}{2} = 266 \times 1087.5$ $a v e r a g e = \frac{Σ}{n} = \frac{Σ a + Σ b}{2 \times 266}$ $= \frac{1184.5 + 1087.5}{2} = 1086 ✓$
	Commented by Shrinava last updated on 15/Mar/23

	$cool dear professor, thank you$
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