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Question Number 189345 by Michaelfaraday last updated on 15/Mar/23

$$solve$$$$\int t^{-6}{(t^2+3)}^{2}dt$$

Answered by Frix last updated on 15/Mar/23

$$=\int (\frac{1}{t^2}+\frac{6}{t^4}+\frac{9}{t^6})dt=-\frac{1}{t}-\frac{2}{t^3}-\frac{9}{5t^5}=-\frac{5t^4+10t^2+9}{5t^5}$$

Commented by Michaelfaraday last updated on 15/Mar/23

$$thankssir$$

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