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Question Number 189417 by sonukgindia last updated on 16/Mar/23

Answered by mehdee42 last updated on 16/Mar/23

(2^(3141) )^2 +(2^x )^2 +(2^(1618) )^2 =(2^a +2^b )^2 =(2^a )^2 +(2^b )^2 +2^(a+b+1) 1)if a=3141 & b=1618 & a+b+1=2x⇒x=2380 2)if a=3141 &b=x&a+b+1=3236⇒x=94 3)a=1618&b=x&a+b+1=6282⇒x=4663 ⇒s=7137

(23141)2+(2x)2+(21618)2=(2a+2b)2=(2a)2+(2b)2+2a+b+11)ifa=3141&b=1618&a+b+1=2x⇒x=23802)ifa=3141&b=x&a+b+1=3236⇒x=943)a=1618&b=x&a+b+1=6282⇒x=4663⇒s=7137

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