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Question Number 189428 by Rupesh123 last updated on 16/Mar/23
Answered by BaliramKumar last updated on 16/Mar/23
tanxtan(60°+x)tan(60°−x)tanx[tan60°+tanx1−tan60°tanx][tan60°−tanx1+tan60°tanx]tanx[3+tanx1−3tanx][3−tanx1+3tanx]tanx[(3−tan2x1−3tan2x][(3tanx−tan3x1−3tan2x]=tan3x
Commented by Rupesh123 last updated on 18/Mar/23
Excellent!
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