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Question Number 189428 by Rupesh123 last updated on 16/Mar/23

Answered by BaliramKumar last updated on 16/Mar/23

tanx tan(60° + x) tan(60° − x)   tanx[((tan60° + tanx)/(1−tan60° tanx))][((tan60° − tanx)/(1 + tan60° tanx))]  tanx[(((√3) + tanx)/(1−(√3) tanx))][(((√3) − tanx)/(1 + (√3) tanx))]  tanx[(((3 − tan^2 x)/(1−3 tan^2 x))]  [(((3tanx − tan^3 x)/(1−3 tan^2 x))] = tan3x

tanxtan(60°+x)tan(60°x)tanx[tan60°+tanx1tan60°tanx][tan60°tanx1+tan60°tanx]tanx[3+tanx13tanx][3tanx1+3tanx]tanx[(3tan2x13tan2x][(3tanxtan3x13tan2x]=tan3x

Commented by Rupesh123 last updated on 18/Mar/23

Excellent!

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