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Question Number 189615 by Rupesh123 last updated on 19/Mar/23

Answered by HeferH last updated on 19/Mar/23

$$16-\mathrm{x}\sqrt{5}=\frac{8\mathrm{x}}{3\sqrt{5}}-\frac{\mathrm{x}}{\sqrt{5}}$$$$16-\mathrm{x}\sqrt{5}=\frac{5\mathrm{x}}{3\sqrt{5}}$$$$48\sqrt{5}-15\mathrm{x}=5\mathrm{x}$$$$\mathrm{x}=\frac{48\sqrt{5}}{20}$$$$\mathrm{x}\sqrt{5}=\frac{48\cdot 5}{20}=\frac{48}{4}=12$$

Commented by HeferH last updated on 19/Mar/23

Commented by Rupesh123 last updated on 19/Mar/23

Excellent!

Commented by Rupesh123 last updated on 19/Mar/23

Excellent!

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