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Question Number 189616 by Rupesh123 last updated on 19/Mar/23

Answered by HeferH last updated on 19/Mar/23

Commented by HeferH last updated on 19/Mar/23

$$\mathrm{say}\mathrm{r}=5\mathrm{m}$$$$\mathrm{m}\left(5\mathrm{m}\right)=(5\mathrm{m}-2\mathrm{x})(5\mathrm{m}+2\mathrm{x})$$$${5\mathrm{m}}^2={25\mathrm{m}}^2-{4\mathrm{x}}^2$$$${4\mathrm{x}}^2={20\mathrm{m}}^2$$$${\mathrm{x}}^2={5\mathrm{m}}^2$$$${5\mathrm{m}}^2+25={25\mathrm{m}}^2$$$$25={20\mathrm{m}}^2$$$${\mathrm{m}}^2=\frac{25}{20}=\frac{5}{4}$$$${\mathrm{x}}^2=\frac{25}{4}\Rightarrow \mathrm{x}=\frac{5}{2}$$

Commented by Rupesh123 last updated on 19/Mar/23

Nice solution, sir!

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