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Question Number 189625 by Rupesh123 last updated on 19/Mar/23

Commented by Rupesh123 last updated on 19/Mar/23

Can you explain?

Answered by Frix last updated on 19/Mar/23

$$...,n-1,n,n,n,n,n,n,n,n+1,n+1,n+1,n+1,n+1,n+1,n+1,n+2,...$$$$n\times k+(n+1)(7-k)=365$$$$n=\frac{k+358}{7};n,k\in \mathbb{N};0⩽k⩽7$$$$\mathrm{only}\mathrm{possibility}\mathrm{is}k=6\Rightarrow n=52$$$$52+52+52+52+52+52+53=365$$

Commented by Rupesh123 last updated on 19/Mar/23

Excellent!

Answered by talminator2856792 last updated on 22/Mar/23

$$\frac{365}{7}=52+\frac{1}{7}$$$$\Rightarrow \mathrm{the}\mathrm{row}\mathrm{is}\mathrm{six}{52}^{\prime }\mathrm{s}\mathrm{and}\mathrm{one}53$$$$\mathrm{middle}\mathrm{number}\mathrm{is}52$$

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