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Question Number 189715 by Rupesh123 last updated on 20/Mar/23

Answered by som(math1967) last updated on 21/Mar/23

$$△ABC\cong △DBE$$$$\Rightarrow AB=DB$$$$BC=BE\Rightarrow \mathrm{\angle }BEC=\mathrm{\angle }BCE$$$$\mathrm{\angle }ACB=34[\mathrm{\angle }ACB=\mathrm{\angle }CBE]$$$$\mathrm{\angle }DEB=\mathrm{\angle }ACB=34$$$$AC\parallel BE\mathrm{\angle }ACE+\mathrm{\angle }BEC=180$$$$34+x+x+34+34=180$$$$2x=180-102$$$$x=39$$

Commented by Rupesh123 last updated on 21/Mar/23

Triangle ABC = Triangle DBE it implies that AB= DE, why?

Commented by som(math1967) last updated on 28/Mar/23

$$AB=DB[correspondingpart$$$$ofcongruencetriangle]$$

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