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Question Number 189786 by sonukgindia last updated on 21/Mar/23
Answered by a.lgnaoui last updated on 22/Mar/23
A∙zz=(eiθ)eiθ=(cosθ+isinθ)z=ezlnz=eeiθln(eiθ)=eln[(eiθ)(cosθ+isinθ)]=e[ln(eiθcosθ×e−θsinθ]=e[ln(eiθcosθ×ln(e−θsinθ)]=ln(eiθcosθ)ln(eθsinθ)=cos(θcosθ)+isin(θcosθ)θsinθ=cos(θcosθ)θsinθ+isin(θcosθ)θsinθ⇒zz=e[cos(θcosθθsinθ×eisin(θcosθθsinθ=ecos(θcosθ)θsinθ[cos(sin(θcosθ)θsinθ)+sin(sin(θcosθθsinθ)]⇒R(zz)=ecos(θcosθ)θsinθ×cos(sin(θcosθ)θsinθ)
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