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Question Number 189823 by Shrinava last updated on 22/Mar/23

$$\mathrm{If}:{\mathrm{x}}_0=1$$$${\mathrm{x}}_{\mathbf{n}+1}=\sqrt{{\mathrm{x}}_{\mathbf{n}}^2+{\mathrm{x}}_{\mathbf{n}}}$$$$\mathrm{Find}:\mathrm{\Omega }=\underset{\mathbf{n}\to \mathrm{\infty }}{\lim }({\mathrm{x}}_{\mathbf{n}}-\frac{\mathrm{n}}{2}+\frac{1}{8}\underset{\mathbf{k}=1}{\sum ^{\mathbf{n}-1}}\frac{1}{{\mathrm{x}}_{\mathbf{k}}})$$

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