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Question Number 189925 by ajfour last updated on 24/Mar/23

Commented by ajfour last updated on 24/Mar/23

$$Regularpentagon.Finda/b.$$

Answered by BaliramKumar last updated on 24/Mar/23

$$\frac{5+\sqrt{5}}{3+\sqrt{5}}=\frac{5-\sqrt{5}}{2}$$

Answered by HeferH last updated on 24/Mar/23

$$\sin 18°=\frac{\sqrt{5}-1}{4}=\frac{2\mathrm{b}-\mathrm{a}}{2\mathrm{b}}$$$$\frac{\sqrt{5}-1}{4}=1-\frac{1}{2}\cdot \frac{\mathrm{a}}{\mathrm{b}}$$$$\frac{\sqrt{5}-1}{2}=2-\frac{\mathrm{a}}{\mathrm{b}}$$$$\frac{\mathrm{a}}{\mathrm{b}}=\frac{5-\sqrt{5}}{2}$$

Commented by HeferH last updated on 24/Mar/23

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