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Question Number 189976 by 073 last updated on 25/Mar/23

Answered by JDamian last updated on 25/Mar/23

$$E$$

Commented by 073 last updated on 25/Mar/23

$$\mathrm{solution}$$

Answered by HeferH last updated on 26/Mar/23

$$\mathrm{let}\mathrm{HD}=\mathrm{x}$$$$\mathrm{DB}=\mathrm{x}\sqrt{2}$$$$\cot \alpha =\frac{1}{\tan \alpha }$$$$\tan \alpha =\frac{\mathrm{x}}{\mathrm{x}\sqrt{2}}=\frac{1}{\sqrt{2}}$$$$\Rightarrow \cot \alpha =\sqrt{2}$$

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